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Saturday, June 27, 2015

UPSC Maths Problems Challenge : A Problem A Day! (Day 15)

Today's sum is based on a series of dates and I believe this is super easy to solve if you are a little careful with your logic.I find this challenge quite intriguing and fell in love with it the moment I saw it at m4maths. Read on to find the solution.





Today's Problem(27/06/2015)


Question Credit : http://www.m4maths.com



Consider the series given below:
4/12/95, 1/1/96, 29/1/96, 26/2/96,......
(a)24/3/96 
(b)25/3/96
(c)26/3/96 
(d)27/3/96



Here,there is a gap of 27 days between each date and the 28th date is considered as the next date.Since any year with 96 at the end would be a leap year (check divisibility rule of 4 in order to avoid confusion),there will be 29 days in the month of February instead of June.So,the required date is 25/3/96,i.e Option (b).
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